Rotate Image Algorithm - Imaging Lingo

 

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This code was originally written by Luke Wigley. I've modified it so you can pass it an image object and also a colour for the background

on rotateImage (anImage, anAngle, anOffSet, aColour)   --------------------------------------------------------------------   -- rotates the supplied image.   -- anAngle is specified in degrees.   -- I Added the image parameter and the colour parameter, aColour.   -- the offset parameter is the pivot point of the rotation.   -- pass along the member.regPoint for rotation around the center point   -- the colour parameter is the background colour of the empty image   -- which you get when you rotate an image.   -- original code by Luke Wigley www.lingoworkshop.com   --------------------------------------------------------------------   aRect = anImage.rect   aQuad = [point(0,0), point(aRect.width,0), point(aRect.width,aRect.height), point(0,aRect.height)]   newQuad = []   anAngle = anAngle * pi/180.0   repeat with j = 1 to 4     thisPoint = aQuad[j]     x = thisPoint[1] - anOffSet[1]     y = thisPoint[2] - anOffSet[2]     thisPoint[1] = x * cos(anAngle) - y * sin(anAngle)     thisPoint[2] = x * sin(anAngle) + y * cos(anAngle)     newQuad[j] = thisPoint + anOffSet   end repeat   newImage = image(anImage.width, anImage.height, anImage.depth)   newImage.floodFill(point(0,0), aColour)   newImage.copyPixels(anImage, newQuad, aRect, [#useFastQuads: 0])   return newImage end